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Seconsett Island, Massachusetts : ウィキペディア英語版 | Seconsett Island, Massachusetts
Seconsett Island is a census-designated place (CDP) in the town of Mashpee in Barnstable County, Massachusetts, United States. The population was 100 at the 2010 census. == Geography == Seconsett Island is located in the southwest part of the town of Mashpee at (41.566734, -70.511950). It is bounded by the town of Falmouth to the northwest, by Hamblin Pond to the northeast, by the Little River to the southeast (with the Monomoscoy Island CDP on the opposite bank), and by Waquoit Bay to the southwest. The only road access is via Meadow Neck Road from Falmouth. According to the United States Census Bureau, the CDP has a total area of , of which , or 4.53%, is water.〔
抄文引用元・出典: フリー百科事典『 ウィキペディア(Wikipedia)』 ■ウィキペディアで「Seconsett Island, Massachusetts」の詳細全文を読む
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